Question

If roots of the equation 3x² + 2(a² + 1) x + (a² – 3a + 2) = 0 are of opposite signs, then a lies in the interval –

• A. (–∞, 1)
• B. (–∞, 0)
• C. (1, 2)
• D. $\left( \frac{3}{2},2 \right)$

Answer 1

Answer: (C)

(1, 2)

Answer 2

Here a = 3 > 0

a² – 3a + 2 < 0 (for opposite roots, a > 0, c < 0)

(a – 1) (a – 2) < 0

a ∈ (1, 2)