Solveeit Logo

Question

Question: If roots of equation x<sup>2</sup> – 2ax + (a<sup>2</sup> + a – 3) = 0 are real and less than 3 the...

If roots of equation x2 – 2ax + (a2 + a – 3) = 0 are real and less

than 3 then

A

a < 2

B

2 £ a £ 3

C

3 < a £ 4

D

a > 4

Answer

a < 2

Explanation

Solution

(1) D ³ 0

(2) f(3) > 0

(3) –b2a\frac{b}{2a} < 3

(1) 4a2 – 4.(a2 + a – 3) ³ 0

a – 3 £ 0 Ž a £ 3

(2) 9 – 6a + a2 + a – 3 > 0

a2 – 5a + 6 > 0

Ž (a – 3) (a – 2) > 0

Ž a > 3, a < 2

(3) + 2a2\frac{2a}{2} < 3 Ž a < 3

Common value of a