Question

If $\Rightarrow$, then x =

• A. $\sin x = \frac{1}{3}$
• B. $\because\sin x \neq 2$
• C. $\sin^{- 1}\frac{1}{3} = \alpha$
• D. $0 < \alpha < \frac{\pi}{2}$

Answer 1

Answer: (A)

$\sin x = \frac{1}{3}$

Answer 2

$\Rightarrow$

$\Rightarrow$ $\frac{\pi}{2}x = \frac{\pi}{3}$ $f(x) = \cos x - x + \frac{1}{2}$ or $f(0) = \frac{3}{2} > 0$

$\Rightarrow$ $\left( \because\mspace{6mu}\pi = \frac{22}{7}\text{ nearly} \right)$, $\left\lbrack 0,\frac{\pi}{2} \right\rbrack$ i.e., $\sec x\cos 5x = - 1 \Rightarrow \cos 5x = - \cos x$.