Question

If $\Rightarrow$, then the general value of $\theta - \frac{\pi}{12} = 2n\pi \pm \frac{\pi}{4} \Rightarrow \theta = 2n\pi \pm \frac{\pi}{4} + \frac{\pi}{12}$ is.

• A. $\tan 3x = 1 \Rightarrow \tan 3x = \tan\frac{\pi}{4}$
• B. $\Rightarrow 3x = n\pi + \frac{\pi}{4}$
• C. $\Rightarrow$
• D. $x = \frac{n\pi}{3} + \frac{\pi}{12}$

Answer 1

Answer: (C)

$\Rightarrow$

Answer 2

$\cos\theta = \frac{(5/2) \pm \sqrt{(25/4) - 4}}{2} = \frac{5 \pm 3}{4}$, also $\Rightarrow$

$\cos\theta = \frac{1}{2} = \cos\left( \frac{\pi}{3} \right) \Rightarrow \theta = 2n\pi \pm \frac{\pi}{3}$ $\cot\theta + \tan\theta = 2\text{ cosec}\theta$.