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Question: If \({Re}(z) = 0 \Rightarrow {Im}(z^{2}) = 0\)and \({Re}(z^{2}) = 0 \Rightarrow {Im}(z^{2}) = 0\), t...

If Re(z)=0⇒Im(z2)=0{Re}(z) = 0 \Rightarrow {Im}(z^{2}) = 0and Re(z2)=0⇒Im(z2)=0{Re}(z^{2}) = 0 \Rightarrow {Im}(z^{2}) = 0, then Re(z)=0⇒Re(z2)=0{Re}(z) = 0 \Rightarrow {Re}(z^{2}) = 0 is.

A

5(−8+6i)(1+i)2=a+ib\frac{5( - 8 + 6i)}{(1 + i)^{2}} = a + ib

B

(a,b)(a,b)

C

(−15,20)( - 15,20)

D

1−i<1+i1 - i < 1 + i

Answer

(−15,20)( - 15,20)

Explanation

Solution

z1+z2z_{1} + z_{2}

Hence (a+c)+i(b+d)(a + c) + i(b + d).