Question
Question: If resonant frequency is f and capacitance become 4 times, then the resonant frequency will be: \[...
If resonant frequency is f and capacitance become 4 times, then the resonant frequency will be:
A. 2f B. 2f C. f D. 4fSolution
Hint: A LC circuit is made up of a capacitance and an inductance. The resonant frequency of a LC circuit is inversely proportional to the square root of capacitance and inductance of the circuit so with increase in capacitance and inductance, the resonant frequency decreases.
Formula used:
The resonance frequency is obtained when reactance of capacitor given as XC=ωC1 matches the reactance of inductance given as XL=ωL where ω=2πν
The resonant frequency of LC circuit is given as
f=2πLC1
where f is the resonant frequency, L is the inductance of the coil and C is the capacitance.
Complete step-by-step answer:
We are given that initially a LC circuit has resonant frequency f. If initial capacitance is C and initial inductance is L then the expression for resonant frequency can be written as
f=2πLC1 ...(i)
Now, the capacitance of the coil has increased 4 times. The new capacitance is given as
C′=4C
The inductance is independent of capacitance and remains same, therefore,
L′=L
But the resonant frequency changes because it is dependent on capacitance of the coil. The expression for new resonant frequency can be written as
f′=2πL′C′1 ...(ii)
Substituting the values of L’ and C’, we get
f′=2πL×4C1 = 21×2πLC1
Using equation (i) here, we get
f′=2f
Therefore, the resonant frequency becomes half on increasing the capacitance four times. Hence, the correct answer is option A.
Note: The condition of resonance is obtained in a circuit when reactance of the capacitance is equal to the reactance of inductance. The resonant frequency signifies the oscillations of electrical energy between inductance and capacitance.