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Question: If resonant frequency is f and capacitance become 4 times, then the resonant frequency will be: \[...

If resonant frequency is f and capacitance become 4 times, then the resonant frequency will be:

A. f2 B. 2f C. f D. f4  {\text{A}}{\text{. }}\dfrac{f}{2} \\\ {\text{B}}{\text{. 2}}f \\\ {\text{C}}{\text{. }}f \\\ {\text{D}}{\text{. }}\dfrac{f}{4} \\\
Explanation

Solution

Hint: A LC circuit is made up of a capacitance and an inductance. The resonant frequency of a LC circuit is inversely proportional to the square root of capacitance and inductance of the circuit so with increase in capacitance and inductance, the resonant frequency decreases.

Formula used:
The resonance frequency is obtained when reactance of capacitor given as XC=1ωC{X_C} = \dfrac{1}{{\omega C}} matches the reactance of inductance given as XL=ωL{X_L} = \omega L where ω=2πν\omega = 2\pi \nu
The resonant frequency of LC circuit is given as
f=12πLCf = \dfrac{1}{{2\pi \sqrt {LC} }}
where f is the resonant frequency, L is the inductance of the coil and C is the capacitance.

Complete step-by-step answer:
We are given that initially a LC circuit has resonant frequency f. If initial capacitance is C and initial inductance is L then the expression for resonant frequency can be written as
f=12πLC ...(i)f = \dfrac{1}{{2\pi \sqrt {LC} }}{\text{ }}...{\text{(i)}}
Now, the capacitance of the coil has increased 4 times. The new capacitance is given as
C=4CC' = 4C
The inductance is independent of capacitance and remains same, therefore,
L=LL' = L
But the resonant frequency changes because it is dependent on capacitance of the coil. The expression for new resonant frequency can be written as
f=12πLC ...(ii)f' = \dfrac{1}{{2\pi \sqrt {L'C'} }}{\text{ }}...{\text{(ii)}}
Substituting the values of L’ and C’, we get
f=12πL×4C  = 12×12πLC  f' = \dfrac{1}{{2\pi \sqrt {L \times 4C} }} \\\ {\text{ = }}\dfrac{1}{2} \times \dfrac{1}{{2\pi \sqrt {LC} }} \\\
Using equation (i) here, we get
f=f2f' = \dfrac{f}{2}
Therefore, the resonant frequency becomes half on increasing the capacitance four times. Hence, the correct answer is option A.

Note: The condition of resonance is obtained in a circuit when reactance of the capacitance is equal to the reactance of inductance. The resonant frequency signifies the oscillations of electrical energy between inductance and capacitance.