Question

If reduction factor of a tangent galvanometer is $900 \,mA$, then the current through it to produce a deflection of $45^{\circ}$ is

• A. 600 mA
• B. 700 mA
• C. 750 mA
• D. 900 mA

Answer 1

Answer: (D)

900 mA

Answer 2

Current $(I)$ flowing in a tangent galvanometer is given by
$I=k \tan \theta \text {. }$
Given, $k$ is reduction factor
$\left(k=900 mA =900 \times 10^{-3} A \right), \theta=45^{\circ}$
$\therefore I=900 \times 10^{-3} \times \tan 45^{\circ}$
$\Rightarrow I=900 \,mA$