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Question

Physics Question on Gravitation

If radius of earth shrinks by 11 % when mass remains same, the acceleration due to gravity on the surface of earth would

A

remain unchanged

B

decrease by 2%

C

become zero

D

increase by 2%.

Answer

decrease by 2%

Explanation

Solution

g=GMR2g = \frac{GM}{R^2} Here g1R2g \propto \frac{1}{R^2} and g1(0.99R)20.98R2g' \propto \frac{1}{(0.99R)^2} \propto \frac{0.98}{R^2} i.e. gg\frac{g'}{g} = 0.98 i.e. g' = 0.98 g Clearly g' decreases by 2%.