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Physics Question on Light - Reflection and Refraction

If R1 and R2 are the radii of curvature, n is the refractive index and f is the focal length, then the lens maker's formula is given by

A

f=(n−1)(1R1−1R2)f=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})

B

f=(n−2)(1R1−1R2)f=(n-2)(\frac{1}{R_1}-\frac{1}{R_2})

C

1f=(n−2)(1R1−1R2)\frac{1}{f}=(n-2)(\frac{1}{R_1}-\frac{1}{R_2})

D

1f=(n−1)(1R1−1R2)\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})

Answer

1f=(n−1)(1R1−1R2)\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})

Explanation

Solution

The correct option is (D): 1f=(n−1)(1R1−1R2)\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})