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Question

Mathematics Question on Probability

If r.v.XB(n=5,P=13)r.v. X \sim B \left(n = 5, P=\frac{1}{3}\right) then P(2<X<4)=P(2 < X < 4) = ______________

A

80243\frac{80}{243}

B

40243\frac{40}{243}

C

40343\frac{40}{343}

D

80343\frac{80}{343}

Answer

40243\frac{40}{243}

Explanation

Solution

Given, XB=(n=5,p=13)X \sim B=\left(n=5, p=\frac{1}{3}\right) p+q=1\because p+q=1 13+q=1\therefore \frac{1}{3}+q=1 q=23\Rightarrow q=\frac{2}{3} $\therefore p(2