Question
Mathematics Question on permutations and combinations
If r,s,t are prime numbers and p , q are the positive integers such th a t LCM of p , q is r2s4t2 then the number of ordered pairs (p, q) is
252
254
225
224
225
Solution
Since, r, s, t are prime numbers,
∴Selection of p and q are as under
p \hspace10mm q \hspace10mm Number of ways
r0 \hspace10mm r2 \hspace10mm 1 way
r1 \hspace10mm r2 \hspace10mm 1 way
r2 \hspace10mm r0,r1,r2 \hspace7mm 3 way
∴ Total number of ways to select, r = 5
Selection of s as under
s0 \hspace10mm s4 \hspace10mm 1 way
s1 \hspace10mm s4 \hspace10mm 1 way
s2 \hspace10mm s4 \hspace10mm 1 way
s3 \hspace10mm s4 \hspace10mm 1 way
s4 \hspace25mm 5 way
∴ Total number of ways to select s = 9
Similarly, the number of ways to select t = 5
∴ Total number of ways = 5 x 9 x 5 = 225