Question
Mathematics Question on Functions
If R be a relation defined as aRbiff∣a−b∣>0, then the relation is
A
reflexive
B
symmetric
C
transitive
D
symmetric and transitive
Answer
symmetric and transitive
Explanation
Solution
We observe the following properties :
Reflexivity - Let a be an arbitrary element.
Then,
∣a−a∣=0>0⇒aRa
This, R is not reflexive on R.
Symmetry - Let a and b be two distinct elements, then (a,b) ∈R
⇒∣a−b∣>0⇒∣b−a∣>0
(∵∣a−b∣=∣b−a∣)
⇒(b,a)∈R
Thus, (a,b)∈R⇒(b,a)∈R. So, R is symmetric.
Transitivity - Let (a,b)∈R and (b,c)∈R.
Then∣a−b∣>0 and ∣b−c∣>0
⇒∣a−c∣>0⇒(a,c)∈R
So, R is transitive.