Question
Question: If Q<sub>1</sub> (x) = x<sup>2</sup> – mx + 1 is negative for value of x in (1, 2), then m lies in ...
If Q1 (x) = x2 – mx + 1 is negative for value of x in (1, 2), then
m lies in the interval –
A
(–3/2, 1/2)
B
(5/2, ∞)
C
(1/2, 5/2)
D
(–∞, –3/2)
Answer
(5/2, ∞)
Explanation
Solution
Q1(1) ≤ 0 & Q1(2) ≤ 0 So m ≥ 2