Question

If q is the angle between the tangents from (–1, 0) to the circle x² + y² –5x + 4y –2 = 0, then q =

• A. 2 tan^–1$\left( \frac{7}{4} \right)$
• B. tan^–1$\left( \frac{7}{4} \right)$
• C. 2 cot^–1$\left( \frac{7}{4} \right)$
• D. cot^–1$\left( \frac{7}{4} \right)$

Answer 1

Answer: (A)

2 tan^–1$\left( \frac{7}{4} \right)$

Answer 2

0 = 2 tan^–1 $\frac{r}{\sqrt{S_{1}}}$