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Question: If product of the roots of the equation 3x<sup>2</sup> – 4x + (loga<sup>2</sup> – log(–a) + 3) = 0 ...

If product of the roots of the equation

3x2 – 4x + (loga2 – log(–a) + 3) = 0 is 1, then 'a' =

A

Not possible

B

– 1

C

1

D

None of these

Answer

– 1

Explanation

Solution

\a>0 Ž a < 0 ....(i)

Now loga2log(a)+33\frac{\log a^{2}–\log(–a) + 3}{3}=1

Ž a2 = – a, Ž a = 0, – 1 ..(ii), form (i) & (ii) Ž a = – 1