Question

If $\pm 3,\mspace{6mu} \pm i$ be the roots of the equation

$\pm 2,\mspace{6mu} \pm i$, then $ix^{2} - 4x - 4i = 0$=

• A. 0
• B. 1
• C. m
• D. $- 2i$

Answer 1

Answer: (D)

$- 2i$

Answer 2

$\mathbf{x}^{\mathbf{2}}\mathbf{+ x + 1 = 0}$ .....(i)

And $x^{2} - 2x + 2 = 0$ .....(ii)

Therefore$x^{2} + 2x + 2 = 0$

$x^{2} + 2x - 2 = 0$

$x^{2} - 18x - 16 = 0$