Question
Question: If per nucleon binding energy for \({}_{3}^{7}Li\) and \({}_{2}^{4}He\) are 5.60 MeV and 7.06 MeV, ...
If per nucleon binding energy for 37Li and 24He
are 5.60 MeV and 7.06 MeV, then the energy released in the nuclear process 37Li+11p→22He4is
A
19.6 MeV
B
2.4 MeV
C
8.4 MeV
D
17.3 MeV
Answer
17.3 MeV
Explanation
Solution
E =