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Question: If p/2 \<a\< 3p/2, then ![](https://cdn.pureessence.tech/canvas_466.png?top_left_x=1558&top_left_y=8...

If p/2 <a< 3p/2, then is equal to -

A

∣αsin⁡α∣\left| \frac { \alpha } { \sin \alpha } \right|

B

∣π−αsin⁡α∣\left| \frac { \pi - \alpha } { \sin \alpha } \right|

C

∣2π−αsin⁡α∣\left| \frac { 2 \pi - \alpha } { \sin \alpha } \right|

D

None of these

Answer

∣π−αsin⁡α∣\left| \frac { \pi - \alpha } { \sin \alpha } \right|

Explanation

Solution

=

= π−αsin⁡α\frac { \pi - \alpha } { \sin \alpha }

(Q for 3π2\frac { 3 \pi } { 2 }sin–1 sin a = p – a)

= π−αsin⁡α\frac { \pi - \alpha } { \sin \alpha } ∣π−αsin⁡α∣\left| \frac { \pi - \alpha } { \sin \alpha } \right|)