Question
Question: If p1 and p2 are the perpendiculars from the origin on the straight lines x sec q + y cosec q = 2a a...
If p1 and p2 are the perpendiculars from the origin on the straight lines x sec q + y cosec q = 2a and x cosq + y sin q = a cos 2q, then-
A
4p12+p22 = a2
B
p12+4p22= a2
C
p12+p22= 4a2
D
p12+p22= a2
Answer
p12+p22= a2
Explanation
Solution
=
= a2 sin2 2q,
p22 = Ž
+
= a2