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Question: If p1 and p2 are the perpendiculars from the origin on the straight lines x sec q + y cosec q = 2a a...

If p1 and p2 are the perpendiculars from the origin on the straight lines x sec q + y cosec q = 2a and x cosq + y sin q = a cos 2q, then-

A

4p12+p224 \mathrm { p } _ { 1 } ^ { 2 } + \mathrm { p } _ { 2 } ^ { 2 } = a2

B

p12+4p22\mathrm { p } _ { 1 } ^ { 2 } + 4 \mathrm { p } _ { 2 } ^ { 2 }= a2

C

p12+p22\mathrm { p } _ { 1 } ^ { 2 } + \mathrm { p } _ { 2 } ^ { 2 }= 4a2

D

p12+p22\mathrm { p } _ { 1 } ^ { 2 } + \mathrm { p } _ { 2 } ^ { 2 }= a2

Answer

p12+p22\mathrm { p } _ { 1 } ^ { 2 } + \mathrm { p } _ { 2 } ^ { 2 }= a2

Explanation

Solution

= = a2 sin2 2q,

p22 = Ž + = a2