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Question

Question: If P (x<sub>1</sub>, y<sub>1</sub>), Q(x<sub>2</sub>, y<sub>2</sub>), R(x<sub>3</sub>, y<sub>3</sub>...

If P (x1, y1), Q(x2, y2), R(x3, y3) and S(x4, y4) are four concyclic points on the rectangular hyperbola xy = c2, the coordinates of orthocentre of the ∆PQR are:

A

(x4, -y4)

B

(x4, y4)

C

(-x4, -y4)

D

(-x4, y4)

Answer

(x4, -y4)

Explanation

Solution

Since, points (xr, yr) is lying on xy = c2 for r = 1, 2, 3, 4

yr=c2xry_{r} = \frac{c^{2}}{x_{r}} for r = 1, 2, 3, 4

Slope of QR is - c2x2x3\frac{c^{2}}{x_{2}x_{3}}.

∴ Equation of line passing through A and perpendicular to QR is

x1x2x3xc2x1y=x12x2x3c4x_{1}x_{2}x_{3}x - c^{2}x_{1}y = {x_{1}}^{2}x_{2}x_{3} - c^{4}... (1)

Similarly, equation of line through Q and perpendicular to PR is

x1x2x3xc2x2y=x1x22x3c4x_{1}x_{2}x_{3}x - c^{2}x_{2}y = x_{1}{x_{2}}^{2}x_{3} - c^{4} ... (2)

(1) - (2) ⇒ y = x1x2x3c2- \frac{x_{1}x_{2}x_{3}}{c^{2}}

x=c4x1x2x3x = \frac{c^{4}}{x_{1}x_{2}x_{3}}.

Thus, orthocentre is again lying on xy = c2 i.e. the fourth point (x4, y4).