Question
Question: If \(p \to \left( { \sim p \vee \sim q} \right)\) is false, then the truth values of \(p\) and \(q\)...
If p→(∼p∨∼q) is false, then the truth values of p and q are respectively,
(A) T, F
(B) F, F
(C) F, T
(D) T, T
Solution
In expressions that include → and other logical operators such as ∼,∨,∧; the order of operations is that → is performed last, while ∼ is performed first.
Complete step-by-step answer:
First of all, we understand the meaning of logical operators such as ∼,∨,∧.
Negation of a statement(∼): Let p be any statement. Then, a statement that denies the statement pis known as negation of the statement p and it is represented by ∼p.
Let p:All triangles are equilateral.
⇒∼p:All triangles are not equilateral.
∧ and ∨: The sign ∧ is used for the word ‘And’ between two statements. For ex- p∧q means ‘p and q’. On the other hand, the sign ∨ is used for the word ‘Or’ between two statements. For ex- p∨q means ‘p or q’.
Given, p→(∼p∨∼q) is false.
Now, let us make the truth table of the given statement:
p | q | ∼p | ∼q | ∼p∨∼q | p→(∼p∨∼q) |
---|---|---|---|---|---|
T | T | F | F | F | F |
T | F | F | T | T | T |
F | T | T | F | T | T |
F | F | T | T | T | T |
From above table, if p→(∼p∨∼q) is false then p and q are both true.
Hence, the answer is option (D).
Note: Another method to solve this problem is described below:
Given, p→(∼p∨∼q) is false.
⇒∼p is false or ∼q is false.
⇒p is true or q is true.
Hence, the answer is option (D) T, T.