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Question: If \(p \to \left( { \sim p \vee \sim q} \right)\) is false, then the truth values of \(p\) and \(q\)...

If p(pq)p \to \left( { \sim p \vee \sim q} \right) is false, then the truth values of pp and qq are respectively,
(A) T, F
(B) F, F
(C) F, T
(D) T, T

Explanation

Solution

In expressions that include \to and other logical operators such as ,,\sim , \vee , \wedge; the order of operations is that \to is performed last, while \sim is performed first.

Complete step-by-step answer:
First of all, we understand the meaning of logical operators such as ,,\sim , \vee , \wedge.
Negation of a statement()\left( \sim \right): Let pp be any statement. Then, a statement that denies the statement ppis known as negation of the statement pp and it is represented by p \sim p.
Let p:p:All triangles are equilateral.
p:\Rightarrow \sim p:All triangles are not equilateral.
\wedge and \vee: The sign \wedge is used for the word ‘And’ between two statements. For ex- pqp \wedge q means ‘pp and qq’. On the other hand, the sign \vee is used for the word ‘Or’ between two statements. For ex- pqp \vee q means ‘pp or qq’.
Given, p(pq)p \to \left( { \sim p \vee \sim q} \right) is false.
Now, let us make the truth table of the given statement:

ppqqp \sim pq \sim qpq \sim p \vee \sim qp(pq)p \to \left( { \sim p \vee \sim q} \right)
TTFFFF
TFFTTT
FTTFTT
FFTTTT

From above table, if p(pq)p \to \left( { \sim p \vee \sim q} \right) is false then pp and qq are both true.
Hence, the answer is option (D).

Note: Another method to solve this problem is described below:
Given, p(pq)p \to \left( { \sim p \vee \sim q} \right) is false.
p\Rightarrow \sim p is false or q \sim q is false.
p\Rightarrow p is true or qq is true.
Hence, the answer is option (D) T, T.