Solveeit Logo

Question

Question: If \( P\left( A \right) = 0.4 \) , \( P\left( B \right) = x \) , \( P\left( {A \cup B} \right) = 0.7...

If P(A)=0.4P\left( A \right) = 0.4 , P(B)=xP\left( B \right) = x , P(AB)=0.7P\left( {A \cup B} \right) = 0.7 and the events A and B are two mutually exclusive events, then the value of x is:
(A) 310\dfrac{3}{{10}}
(B) 12\dfrac{1}{2}
(C) 25\dfrac{2}{5}
(D) 15\dfrac{1}{5}

Explanation

Solution

Hint : Here, P(x)P(x) denotes the probability of some event. Thus, P(A)P(A) means the probability of event A. We are given that the events A and B are mutually exclusive events. So, there is nothing common between the two events. Also, P(AB)P\left( {A \cup B} \right) means the probability of ABA \cup B , that is either of the two events A and B occur. So, we will make use of the formula P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) to solve the problem and find the value of x.

Complete step-by-step answer :
In the questions, we are given that probability of event A is P(A)=0.4P\left( A \right) = 0.4 . Also, Probability that either of the two events A and B occur is P(AB)=0.7P\left( {A \cup B} \right) = 0.7 .
Now, we are given the probability of event B as variable x. So, we have to find the value of x using the formula P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) .
We are also provided with the fact that A and B are two mutually exclusive events. So, there is nothing common in the two events A and B and they cannot happen simultaneously.
Hence, the probability of the two events A and B happening together is zero.
Now, we will use the formula P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) to solve the problem and find the value of x.
So, we get, P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B)
We know that the probability of the two events A and B happening together is zero. So, we have, P(AB)=0P(A \cap B) = 0 . Substituting this into the formula, we get,
P(AB)=P(A)+P(B)0\Rightarrow P(A \cup B) = P(A) + P(B) - 0
Substituting the values of P(A)P(A) and P(AB)P\left( {A \cup B} \right) , we get,
0.7=0.4+P(B)\Rightarrow 0.7 = 0.4 + P(B)
We also know that P(B)=xP\left( B \right) = x . So, we get,
x=0.70.4\Rightarrow x = 0.7 - 0.4
Simplifying the calculations, we get,
x=0.3\Rightarrow x = 0.3
So, we get the value of x as 0.30.3 .
We can also write 0.30.3 in fractional form as 310\dfrac{3}{{10}} .
So, option (A) is the correct answer.
So, the correct answer is “Option A”.

Note : These problems are the combinations of sets and probability, so, the concepts of both of the topics are used in these. Here the formula, P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) is used. This formula is a restructured version of the formula of sets, which is, n(AB)=n(A)+n(B)n(AB)n(A \cup B) = n(A) + n(B) - n(A \cap B) where, n(x)n(x) denotes the number of elements in set x.x. This formula is modified into the formula of probability by dividing on both sides by n(U)n(U) , where UU is the universal set.