Question: If P is a point on the hyperbola 16x2 – 9y2 = 144 whose foci are S1...

Question

If P is a point on the hyperbola 16x² – 9y² = 144 whose foci are S₁ and S₂, then PS₁ ~ PS₂ =

Answer 1

16x² – 9y² = 144 Ž $\frac{x^{2}}{9}$ – $\frac{y^{2}}{16}$ = 1

PS₁ – PS₂ = Transverse axis

Ž PS₁ – PS₂ = 2a = 6

Question: If P is a point on the hyperbola 16x<sup>2</sup> – 9y<sup>2</sup> = 144 whose foci are S<sub>1</sub>...