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Question

Mathematics Question on Conditional Probability

If P(A∪B)=0.8,P(A∩B)=0.3P(A \cup B) = 0.8, P(A \cap B) = 0.3 then P(Aˉ)+P(Bˉ)P (\bar{A} ) + P(\bar{B}) =

A

0.3

B

0.5

C

0.7

D

0.9

Answer

0.9

Explanation

Solution

P(Aˉ)+P(Bˉ)=2−[P(A∪B)+P(A∩B)]P ( \bar{A} ) + P(\bar{B}) = 2 - [P(A \cup B) + P(A \cap B)]