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Question: If \(P ( A ) = 2 / 3\) , \(P ( B ) = 1 / 2\) and \(P ( A \cup B ) = 5 / 6\) then events A and B are...

If P(A)=2/3P ( A ) = 2 / 3 , P(B)=1/2P ( B ) = 1 / 2 and P(AB)=5/6P ( A \cup B ) = 5 / 6 then events A and B are

A

Mutually exclusive

B

Independent as well as mutually exhaustive

C

Independent

D

Dependent only on A

Answer

Mutually exclusive

Explanation

Solution

P(AB)=P(A)+P(B)P(AB)P ( A \cup B ) = P ( A ) + P ( B ) - P ( A \cap B )

56=23+12P(AB)\frac { 5 } { 6 } = \frac { 2 } { 3 } + \frac { 1 } { 2 } - P ( A \cap B ) P(AB)=0\Rightarrow P ( A \cap B ) = 0

∴ Events A and B are mutually exclusive.