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Question: If \(\overset{\rightarrow}{P}.\overset{\rightarrow}{Q} = PQ,\) then angle between \(\overset{\righta...

If P→.Q→=PQ,\overset{\rightarrow}{P}.\overset{\rightarrow}{Q} = PQ, then angle between P→\overset{\rightarrow}{P}and Q→\overset{\rightarrow}{Q} is

A

0°

B

30°

C

45°

D

60°

Answer

0°

Explanation

Solution

cos⁡θ=P→.Q→PQ=1\cos\theta = \frac{\overrightarrow{P}.\overrightarrow{Q}}{PQ} = 1∴ θ=0∘\theta = 0{^\circ}