Question
Question: If \(| ⥂ \overrightarrow{A} + \overrightarrow{B} ⥂ | = | ⥂ \overrightarrow{A} ⥂ | + | ⥂ ⥂ \overright...
If ∣⥂A+B⥂∣=∣⥂A⥂∣+∣⥂⥂B⥂∣, then angle between \overrightarrow{A} and \overrightarrow{B}$ will be-
A
(a)900
A
(b)1200
A
(c)00
A
(d)600
Explanation
Solution
(c)
Resultant of two vectors A→ and B→ can be given by R→=A→+B→
∣R→∣=∣A→+B→∣=A2+B2+2ABcosθ
If θ=0∘ then ∣R→∣=A+B=∣A→∣+∣B→∣