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Question: If \(| ⥂ \overrightarrow{A} + \overrightarrow{B} ⥂ | = | ⥂ \overrightarrow{A} ⥂ | + | ⥂ ⥂ \overright...

If A+B=A+⥂⥂B| ⥂ \overrightarrow{A} + \overrightarrow{B} ⥂ | = | ⥂ \overrightarrow{A} ⥂ | + | ⥂ ⥂ \overrightarrow{B} ⥂ |, then angle between \overrightarrow{A} and \overrightarrow{B}$ will be-

A

(a)90090^{0}

A

(b)1200120^{0}

A

(c)000^{0}

A

(d)60060^{0}

Explanation

Solution

(c)

Resultant of two vectors A\overset{\rightarrow}{A} and B\overset{\rightarrow}{B} can be given by R=A+B\overset{\rightarrow}{R} = \overset{\rightarrow}{A} + \overset{\rightarrow}{B}

R=A+B=A2+B2+2ABcosθ|\overset{\rightarrow}{R}| = |\overset{\rightarrow}{A} + \overset{\rightarrow}{B}| = \sqrt{A^{2} + B^{2} + 2AB\cos\theta}

If θ=0\theta = 0{^\circ} then R=A+B=A+B|\overset{\rightarrow}{R}| = A + B = |\overset{\rightarrow}{A}| + |\overset{\rightarrow}{B}|