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Question: If \(\overrightarrow{A} = 2\widehat{i} + 3\widehat{j}\), \(\overrightarrow{B} = 5\widehat{i}–6\wideh...

If A=2i^+3j^\overrightarrow{A} = 2\widehat{i} + 3\widehat{j}, B=5i^6j^\overrightarrow{B} = 5\widehat{i}–6\widehat{j} and C=A+B\overrightarrow{C} = \overrightarrow{A} + \overrightarrow{B}, the magnitude of C is –

A

58\sqrt{58}units

B

61\sqrt{61}units

C

4 units

D

10 units

Answer

58\sqrt{58}units

Explanation

Solution

C\overset{\rightarrow}{C} = A+B\overset{\rightarrow}{A} + \overset{\rightarrow}{B} = 7i^\widehat{i} – 3j^\widehat{j} ̃ |C\overset{\rightarrow}{C} | = 58\sqrt{58} units