Question

If $\overrightarrow { \mathrm { a } }$ = $\hat { \mathrm { i } }$ + + and $\overrightarrow { \mathrm { b } }$ = $\hat { \mathrm { i } }$ – 2 +, then the vector such that. $\overrightarrow { \mathrm { c } }$ = 2 and × $\overrightarrow { \mathrm { c } }$ = $\overrightarrow { \mathrm { b } }$ is-

• A. $\frac { 1 } { 3 }$ ( $\hat { \mathrm { i } }$ – 2 + )
• B. $\frac { 1 } { 3 }$ (– $\hat { \mathrm { i } }$ + 2 + 5)
• C. $\frac { 1 } { 3 }$ ( $\hat { \mathrm { i } }$ + 2 – 5)
• D. $\frac { 1 } { 3 }$ (– $\hat { \mathrm { i } }$ + 2 – 5)

Answer 1

Answer: (B)

$\frac { 1 } { 3 }$ (– $\hat { \mathrm { i } }$ + 2 + 5)

Answer 2

× =× (× $\overrightarrow { \mathrm { c } }$ ) = (. $\overrightarrow { \mathrm { c } }$ )– (.) $\overrightarrow { \mathrm { c } }$

= 2 – 3 $\overrightarrow { \mathrm { c } }$

× = = 3 $\hat { \mathrm { i } }$ – 3

\ $\overrightarrow { \mathrm { c } }$ =$\frac { 1 } { 3 }$ (2 – × ) = $\frac { 1 } { 3 }$ (– $\hat { \mathrm { i } }$ + 2 + 5)