Question

If $\overrightarrow F=2z\hat{i}-x\hat{j}+y\hat{k}$ and Vis the region bounded by the surface x=0,y=0,x=2,y=4,z=x2,z=2, then value of $\iiint\limits_V\overrightarrow FdV$is

• A. $\frac{32}{15}(3\hat{j}+5\hat{k})$
• B. $\frac{32}{15}(3\hat{i}+5\hat{k})$
• C. $\frac{32}{15}(5\hat{i}+3\hat{k})$
• D. $\frac{32}{15}(3\hat{i}+5\hat{j})$

Answer 1

Answer: (B)

$\frac{32}{15}(3\hat{i}+5\hat{k})$

Answer 2

The correct answer is(B): $\frac{32}{15}(3\hat{i}+5\hat{k})$