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Question

Mathematics Question on Vector Algebra

If a\overrightarrow{a} and b1\overrightarrow{b_1} are two unit vectors such that a+2b\overrightarrow{a}+2\overrightarrow{b} and 5a4b5\overrightarrow{a}-4\overrightarrow{b} b, are perpendicular to each other, then the angle between aandb\overrightarrow{a} and \overrightarrow{b} is

A

4545^\circ

B

6060^\circ

C

cos1(13)cos^{-1}\Bigg(\frac{1}{3}\Bigg)

D

cos1(27)cos^{-1}\Bigg(\frac{2}{7}\Bigg)

Answer

6060^\circ

Explanation

Solution

Since, (a+2b).(5a4a)=0(\overrightarrow{a}+2\overrightarrow{b}).(5\overrightarrow{a}-4\overrightarrow{a})=0
\Rightarrow \hspace25mm 5|\overrightarrow{a}|^2+6\overrightarrow{a}.\overrightarrow{b}-8|\overrightarrow{b}|^2=0
\Rightarrow \hspace35mm 6\overrightarrow{a}.\overrightarrow{b}=3 [\because |\overrightarrow{a}|=|\overrightarrow{b}|=1]
\Rightarrow \hspace35mm \cos\theta =\frac{1}{2}\Rightarrow \theta=60^\circ