Solveeit Logo

Question

Physics Question on Vectors

If A=(2i^+3j^k^)m\overrightarrow A=(2\hat i+3\hat j−\hat k)m and B=(i^+2j^+2k^)m\overrightarrow B=(\hat i+2\hat j+2\hat k)m. The magnitude of component of vector A\overrightarrow A along vector B\overrightarrow B will be ______mm.

Answer

A  cosθ=A.BBA\; cos \theta = \frac{\overrightarrow A.\overrightarrow B}{|\overrightarrow B|}

= 2+623\frac{2+6-2}{3}

= 63\frac{6}{3}

=22