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Question: If $\overline{AB}=(2i+3j-k)$ and A(1, 2, -1) is the given point, then the co-ordinates of B are...

If AB=(2i+3jk)\overline{AB}=(2i+3j-k) and A(1, 2, -1) is the given point, then the co-ordinates of B are

A

(3, 5, 2)

B

(3, 5, -2)

C

(2, 4, 1)

D

(2, 4, -1)

Answer

(3, 5, -2)

Explanation

Solution

We have:

AB=2,3,1,A=(1,2,1)\overrightarrow{AB} = \langle 2,3,-1 \rangle,\quad A=(1,2,-1)

Coordinates of BB are:

B=A+AB=(1+2,  2+3,  1+(1))=(3,5,2)B = A + \overrightarrow{AB} = (1+2,\; 2+3,\; -1+(-1)) = (3,5,-2)

Add the given vector to point A to get the coordinates of B.