If one root of the quadratic equation (a(b-c)x^2+b(c-a)x+c(a... | Mathematics | SolveeIt

If one root of the quadratic equation $a(b-c)x^2+b(c-a)x+c(a-b)=0$ is 1, then the other root is

$\frac{b(c-a)}{a(b-c)}$

$\frac{a(b-c)}{c(a-b)}$

$\frac{a(b-c)}{b(c-a)}$

$\frac{c(a-b)}{a(b-c)}$

Answer

$\frac{c(a-b)}{a(b-c)}$

Explanation

The correct option is (D): $\frac{c(a-b)}{a(b-c)}$

Mathematics Question on Quadratic Equations