Question

If one root of $( - \infty, - \sqrt{2}) \cup (\sqrt{2},\infty)$ is reciprocal of the other, then $( - \infty, - 1) \cup (1,\infty)$ =

• A. 0
• B. 5
• C. 1/6
• D. 6

Answer 1

Answer: (B)

5

Answer 2

Let first root $l^{4}x^{2} + nl(m^{2} - 2nl)x - n^{4} = 0$ and second root =$l^{4}x^{2} - nl(m^{2} + 2nl)x + n^{4} = 0$

Then $p^{2} = 4q + 1$.