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Question: If one of the lines of \[m{y^2} + \left( {1 - {m^2}} \right)xy - m{x^2} = 0\] is bisector of the ang...

If one of the lines of my2+(1m2)xymx2=0m{y^2} + \left( {1 - {m^2}} \right)xy - m{x^2} = 0 is bisector of the angle between the lines xy=0xy = 0, then m is
A.1
B.2
C.12\dfrac{{ - 1}}{2}
D.-1

Explanation

Solution

Given line is a pair of straight lines. And one of its lines is a bisector of angle between the lines xy=0xy = 0. Thus we will compare the pair of straight lines with the respective lines and then will find the value of m.

Complete step-by-step answer:
Line xy=0xy = 0 means bisector of coordinate system.

Thus, x=y or x=-y are the two lines.
Now given that,
my2+(1m2)xymx2=0m{y^2} + \left( {1 - {m^2}} \right)xy - m{x^2} = 0
Multiplying xy with the middle terms,

my2+xym2xymx2=0 y(my+x)mx(my+x)=0 (ymx)(my+x)=0 \Rightarrow m{y^2} + xy - {m^2}xy - m{x^2} = 0 \\\ \Rightarrow y(my + x) - mx(my + x) = 0 \\\ \Rightarrow \left( {y - mx} \right)\left( {my + x} \right) = 0 \\\

Thus , two lines that appear are
ymx=0\Rightarrow y - mx = 0 or my+x=0my + x = 0
y=mx\Rightarrow y = mx or y=xmy = - \dfrac{x}{m}
Thus comparing with the two lines above m=±1m = \pm 1.
Thus correct options are A and D.

Note: In this problem the key point is only that the line xy=0xy = 0 is the coordinate system and students should know the two lines of that system. And need to compare the pair of straight lines with it to get the value of m.