Question
Mathematics Question on integral
If one of the cube roots of 1 be ω, then|11+ω2ω21−i−1ω2−1−i−1+ω−1|=
A
(A) ω
B
(B) i
C
(C) 1
D
(D) 0
Answer
(D) 0
Explanation
Solution
Explanation:
C2→C2−C3C3→C3+C2C3→C3+ωC1C2→C2−C1
If one of the cube roots of 1 be ω, then|11+ω2ω21−i−1ω2−1−i−1+ω−1|=
(A) ω
(B) i
(C) 1
(D) 0
(D) 0
Explanation:
C2→C2−C3C3→C3+C2C3→C3+ωC1C2→C2−C1