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Question: If one end of the diameter of a circle which touches x-axis is (3, 4) then the locus of other end of...

If one end of the diameter of a circle which touches x-axis is (3, 4) then the locus of other end of the diameter of the circle is/an-

A

Parabola

B

Hyperbola

C

Ellipse

D

Circle

Answer

Parabola

Explanation

Solution

Let other end is (h, k)

so centre º (h+32,k+42)\left( \frac{h + 3}{2},\frac{k + 4}{2} \right) touching x- axis means

r = k+42\frac{k + 4}{2}

So k+42\frac{k + 4}{2}= (h+323)2+(k+424)2\sqrt{\left( \frac{h + 3}{2} - 3 \right)^{2} + \left( \frac{k + 4}{2} - 4 \right)^{2}}

Hence locus is x2 – 6x – 16y + 9 = 0

̃ parabola