Question
Question: If one end of a diameter of the circle x<sup>2</sup> + y<sup>2</sup> – 4x – 6y + 11 = 0 be (3, 4) t...
If one end of a diameter of the circle
x2 + y2 – 4x – 6y + 11 = 0 be (3, 4) then the other end is –
A
(0, 0)
B
(1, 1)
C
(1, 2)
D
(2, 1)
Answer
(1, 2)
Explanation
Solution
Centre is (2, 3) one end is (3, 4) let the other end (x, y)
(3+x/2, 4+y/2) = (2, 3) Ž \ (x, y) = (1, 2)