Question
Question: If one AM ‘a’ and two GM’s p and q are inserted between any two given numbers then \({p^3} + {q^3} =...
If one AM ‘a’ and two GM’s p and q are inserted between any two given numbers then p3+q3=kapq, then find k.
Solution
First write the numbers in terms of arithmetic mean. After that use the geometric mean and calculate the value p2. Now multiply the term by p to get p3. Similarly, calculate for q3. Now add both p3 and q3 simplify it. Then compare the result with the given part and get the value of k.
Formula used:
The arithmetic mean is calculated by,
AM=2a+b
The geometric mean is calculated by,
GMa=bGM
Cross multiply the value,
GM2=ab
where a and b are numbers
Complete step-by-step answer:
Given:- p3+q3=kapq …..(1)
Let the two numbers be x and y.
Then, the arithmetic mean ‘a’ will be,
a=2x+y
Cross multiply the value to get the equation,
x+y=2a …..(2)
Now, p and q be the GM between x and y,
Then, x, p, q, y is in GP.
Now, for the geometric mean between x, p, and q, the ratios are equal.
px=qp
Cross multiply the value to get the equation,
p2=xq
Now multiply both sides by p,
p3=pqx ….(3)
Now, for the geometric mean between p, q, and y, the ratios are equal.
qp=yq
Cross multiply the value to get the equation,
q2=py
Now multiply both sides by q,
q3=pqy ….(4)
Now add both equations (3) and (4),
p3+q3=pqx+pqy
Take pq common from the right side of the equation,
p3+q3=pq(x+y)
Substitute the value of x+y from the equation (2),
p3+q3=pq×2a
Compare the above equation with equation (1),
kapq=2apq
Cancel out common factors from both sides,
k=2
Hence, the value of k is 2.
Note: The arithmetic mean is the simplest and most widely used measure of a mean, or average. It simply involves taking the sum of a group of numbers, then dividing that sum by the count of the numbers used in the series.
The geometric mean is the average rate of return of a set of values calculated using the products of the terms.