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Physics Question on thermal properties of matter

If on heating liquid through 80∘C80^{\circ} C, the mass expelled is (1/100) th(1/100)\,th of mass still remaining, the coefficient of apparent expansion of liquid is :

A

1.25×10−4/∘C1.25 \times 10^{-4} /{ }^{\circ} C

B

12.5×10−4/∘C12.5 \times 10^{-4} /{ }^{\circ} C

C

1.25×10−5/∘C1.25 \times 10^{-5} /{ }^{\circ} C

D

none of these

Answer

1.25×10−4/∘C1.25 \times 10^{-4} /{ }^{\circ} C

Explanation

Solution

From relation γapparent = mass expelled  mass remained ×t\gamma_{\text {apparent }} =\frac{\text { mass expelled }}{\text { mass remained } \times t } =x100x×80=18000=\frac{\frac{x}{100}}{x \times 80}=\frac{1}{8000} =1.25×10−4/∘C=1.25 \times 10^{-4} /{ }^{\circ} C