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Question

Mathematics Question on Complex Numbers and Quadratic Equations

If ω\omega is an imaginary cube root of unity, then (1 + ω\omega - ω2)7\omega^2)^7 is equal to

A

128ω\omega

B

-128ω\omega

C

128ω2\omega^2

D

-128ω2\omega^2

Answer

-128ω2\omega^2

Explanation

Solution

(1+ωω2)7=(ω2ω2)7[1+ω+ω2=0](1+\omega-\omega^2)^7=(-\omega^2-\omega^2)^7 \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, [\because 1+\omega+\omega^2=0]
=(2ω2)7=(2)7ω14=128ω2=(-2\omega^2)^7=(-2)^7\omega^{14}=-128 \omega^2