Question
Question: If \([OH^-]= 5.0 × 10^{-5}\) M then pH will be: A. \[5-\log 5\] B. \[9+\log 5\] C. \[\log 5-5\...
If [OH−]=5.0×10−5 M then pH will be:
A. 5−log5
B. 9+log5
C. log5−5
D. log5−9
Solution
The pH of a solution is negative-logarithm of hydrogen ion concentration. As with the hydrogen-ion concentration, the concentration of the hydroxide ion can be expressed logarithmically by the pOH. The pOH of a solution is the negative-logarithm of hydroxide-ion concentration in that solution. Regardless of what is added to the solution the sum of pH and pOH will be always 1.0 x 10−14 at 25oC.
⇒pH+pOH=14
Complete step by step answer:
Given that,[OH-]= 5.0 × 10-5, hence the pOH will be,
⇒pOH=−log[OH−]
=−log(5×10−5)
pOH=5−log5
Now, we have known that,
⇒pH+pOH=14
⇒pH=14−pOH
$$\Rightarrow {{p}{H}}=9+\log 5$$
Hence, the correct option is B.
Note:
pH is a measure of how acidic/basic water is. The range goes from 0 to 14, with 7 being neutral. When pH of less than 7 indicates acidity, whereas a pH of greater than 7 indicates a base.The pH and pOH are really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.