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Question: If O is the origin and Q is a variable point of \({{y}^{2}}=x\). Find the locus of the mid-point of ...

If O is the origin and Q is a variable point of y2=x{{y}^{2}}=x. Find the locus of the mid-point of OQ.

Explanation

Solution

We first find the parametric form of the equation of parabola y2=x{{y}^{2}}=x. We find the value of the parameter aa. We take the point Q and find the midpoint of OQ. The locus will be defined for the midpoint using the formula of (c+m2,d+n2)\left( \dfrac{c+m}{2},\dfrac{d+n}{2} \right).

Complete step by step solution:
O is the origin and it will be considered as the coordinates of (0,0)\left( 0,0 \right).
Q is a variable point of y2=x{{y}^{2}}=x. Any arbitrary point of a parabola will be considered as the coordinates of (at2,2at)\left( a{{t}^{2}},2at \right). It is the parametric form of the parabola. We need to find the value of aa.
So, (2at)2=at24a2=a{{\left( 2at \right)}^{2}}=a{{t}^{2}}\Rightarrow 4{{a}^{2}}=a. Now the value of aa cannot be 0.

& 4{{a}^{2}}=a \\\ & \Rightarrow 4a=1 \\\ & \Rightarrow a=\dfrac{1}{4} \\\ \end{aligned}$$ The parametric coordinates of a point on ${{y}^{2}}=x$ will be $Q=\left( \dfrac{{{t}^{2}}}{4},\dfrac{t}{2} \right)$. Now we need to find the locus of the mid-point of OQ. The general formula of mid-point of two points $A\left( c,d \right)$ and $B\left( m,n \right)$ will be $\left( \dfrac{c+m}{2},\dfrac{d+n}{2} \right)$. Following the formula, we get the midpoint of OQ as $\left( h,k \right)\equiv \left( \dfrac{\dfrac{{{t}^{2}}}{4}+0}{2},\dfrac{\dfrac{t}{2}+0}{2} \right)=\left( \dfrac{{{t}^{2}}}{8},\dfrac{t}{4} \right)$. We get the value of $t$ as $k=\dfrac{t}{4}$ which gives $t=4k$. We put the value in the equation of $h=\dfrac{{{t}^{2}}}{8}$ and get $h=\dfrac{{{\left( 4k \right)}^{2}}}{8}=2{{k}^{2}}$. We now change the equation $h=2{{k}^{2}}$ to normal form and get $x=2{{y}^{2}}$. **Therefore, the locus of the mid-point of OQ is $x=2{{y}^{2}}$.** We can see the graph of the parabola $x=y^2$ (red) and the locus of the midpoint of OQ $x=2y^2$ (green)f below. ![](https://www.vedantu.com/question-sets/952cad02-429b-47ce-8239-c06079c0a7e7586127766793147015.png) **Note:** We need to be careful about the vertex of the parabola. As it is the origin $\left( 0,0 \right)$, we can take the parametric coordinates as $\left( a{{t}^{2}},2at \right)$.