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Question: If O is the origin and A is the point (a, b, c) then the equation of the plane through A and at righ...

If O is the origin and A is the point (a, b, c) then the equation of the plane through A and at right angles to OA is

A

a(xa)b(yb)c(zc)=0a(x - a) - b(y - b) - c(z - c) = 0

B

a(x+a)+b(y+b)+c(z+c)=0a(x + a) + b(y + b) + c(z + c) = 0

C

a(xa)+b(yb)+c(zc)=0a(x - a) + b(y - b) + c(z - c) = 0

D

None of these

Answer

a(xa)+b(yb)+c(zc)=0a(x - a) + b(y - b) + c(z - c) = 0

Explanation

Solution

Normal will be OA whose direction ratios are a0a - 0 b0b - 0 c0c - 0 i.e., a, b, c. It passes through A(a,b,c)A ( a , b , c )

\therefore Equation of required plane is, a(xa)+b(yb)+c(zc)=0a ( x - a ) + b ( y - b ) + c ( z - c ) = 0.