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Question: If O be the origin and the co-ordinates of P be (1, 2, –3), then the equation of the plane passing t...

If O be the origin and the co-ordinates of P be (1, 2, –3), then the equation of the plane passing through P and perpendicular to OP is

A

x2y+3z+12=0x - 2y + 3z + 12 = 0

B

2x+3yz11=02x + 3y - z - 11 = 0

C

x+2y3z14=0x + 2y - 3z - 14 = 0

D

x+2y3z=0x + 2y - 3z = 0

Answer

x+2y3z14=0x + 2y - 3z - 14 = 0

Explanation

Solution

Equation of plane passing through P(1,2,3)P ( 1,2 , - 3 ) and

perpendicular to OP is,

1(x1)+2(y2)3(z+3)=01 ( x - 1 ) + 2 ( y - 2 ) - 3 ( z + 3 ) = 0 or x+2y3z14=0x + 2 y - 3 z - 14 = 0.