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Question

Mathematics Question on Three Dimensional Geometry

If O = (0, 0, 0), P = (4, 3, -5), Q = (-2, 1, -8), cosPOQ=abc\cos\angle POQ = \frac{a}{\sqrt{b}\sqrt{c}} and b > c then b - c =

A

19

B

6950\sqrt{69} - \sqrt{50}

C

-19

D

17

Answer

19

Explanation

Solution

D.r?? of OP = (4,3,-5), D.r?? of OQ = (-2,1 - 8) cosOPQ=8+34050.69cos \angle {OPQ} = \frac{-8+3-40}{\sqrt{50 } .\sqrt{69}} b - c = 69 - 50 b - c = 19