Question

If number of stereoisomers in the complex $[M_{ABCDEF}]$ is x; and number of stereoisomers in the complex $[M_{A_2BCDE}]$ is y then value of $\frac{x-y}{3}$ would be

Answer 1

5

Answer 2

For complex $[M_{ABCDEF}]$, there are 15 geometric isomers. All are chiral, so there are $15 \times 2 = 30$ stereoisomers. Thus, $x=30$.

For complex $[M_{A_2BCDE}]$, there are 8 geometric isomers. Among these, 1 is meso (optically inactive) and 7 are chiral (optically active). The number of stereoisomers is the sum of the number of meso isomers and twice the number of chiral isomers, which is $1 + 2 \times 7 = 15$. Thus, $y=15$.

The value of $\frac{x-y}{3} = \frac{30-15}{3} = \frac{15}{3} = 5$.