Question

If normal at (1,2) to the parabola y² = 4x meets the parabola again at (t², 2t) then t is equal to

• A. –2
• B. –1
• C. – 3
• D. None of these

Answer 1

Answer: (C)

– 3

Answer 2

If the normal at t₁ meets the parabola at t₂, then

t₂ = –t₁ –$\frac{2}{t_{1}}$.

Here t₁ = 1 and t₂ = t ⇒ t = –1 –$\frac{2}{1}$= -3.