Question

If nearly $10^{5}$coulomb liberate 1 gm equivalent of aluminium, then the amount of aluminium (equivalent weight 9) deposited through electrolysis in 20 minutes by a current of 50 amp will be

• A. 0.6 gm
• B. 0.09 gm
• C. 5.4 gm
• D. 10.8 gm

Answer 1

Answer: (C)

5.4 gm

Answer 2

$m = Zit$ or $m \propto it$

∴ $\frac{m_{1}}{m_{2}} = \frac{i_{1}t_{1}}{i_{2}t_{2}}$ ⇒$\frac{9}{m_{2}} = \frac{10^{5}}{50 \times 20 \times 60}$ ⇒$m_{2} = 5.4gm$